Question

Quadrilateral ABCD is located at A(−2, 2), B(−2, 4), C(2, 4), and D(2, 2). The quadrilateral is then transformed using the rule (x − 2, y + 8) to form the image A'B'C'D'. What are the new coordinates of A', B', C', and D'? Describe what characteristics you would find if the corresponding vertices were connected with line segments.

Answer 1

Explanation:

it also made the thing look like a rectangular prism

Answer 2

Given vertices of the Quadrilateral ABCD :

A(−2, 2),

B(−2, 4),

C(2, 4), and

D(2, 2).

The quadrilateral is then transformed using the rule (x − 2, y + 8).

Let us find the coordinate A', B', C', and D' by rule (x − 2, y + 8).

A(−2, 2) ---> (-2-2 , 2+8) = (-4, 10)

B(−2, 4) ---> (-2-2, 4+8) = (-4, 12)

C(2, 4), ---> ( 2-2, 4+8) = (0, 12)

D(2, 2) ---> (2-2, 2+8) = (0, 10).

So, the coordinates of A', B', C', and D' are

A'(-4, 10), B'(-4, 12), C'(0, 12), and D'(0, 10).

For the new coordinates we get we can say that each of the coordinate A', B', C', and D' moved 2 unit left and 8 units up.