Question

Whata the answer for this pythagorean theorem?

Answer 1

To do this we must rearrange the original pythagorean theorem formula...

`\boxed{A^2+B^2=C^2}` →
`\boxed{A^2=C^2-B^2}`

Now, we need to input the given numbers into our new formula...

`\boxed{A^2=C^2-B^2}` →
`\boxed{A^2=5^2-4^2}`

Alright, now that we have done that lets find out what 5² and 4² equals...

`\left[\begin{array}{ccc}5^2(5*5)=25\\4^2(4*4)=16\end{array}\right]`

Now that we have done that we need to subtract 16 from 25...

`\boxed{25-16=9}`

We need to find the square root of our answer (9) to get our final answer.

`\boxed{√(9)=3}`

The square root of 9 equals 3. Thus, our final answer is B, x=3.

Answer 2

The Pythagorean Theorem is a² + b² = c², where c is the hypotenuse of a right triangle. The hypotenuse of the triangle is always opposite the right angle; in this case, the hypotenuse measures 5 units. To find the missing side length, plug the given values into the theorem and solve algebraically for x.

x² + 4² = 5² (plug in values for hypotenuse and side length)
x² + 16 = 25 (square 4 and 5)
x² = 9 (subtract 16 from both sides)
x = 3 (take the square root of both sides)

Answer:
x = 3