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The law of cosines a2+b2-2abcosC=c2. Find the value of 2abcosC.

The law of cosines a2+b2-2abcosC=c2. Find the value of 2abcosC.-example-1

1 Answer

4 votes
A = 4
B = 3
C = 2

We need to find cos(C)


4 = 16 + 9 - 2(2)(3)(cos(C))

-21 = -12 * cos(C)

cos (C)=  1.75

The answer is
2 * 3 * 4 * 1.75 = 42





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User Fantasia
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