Question

I don't have the calculator :( Add some details

Thanks!

Answer 1

`\sin2x-\sin x=2\sin x\cos x-\sin x=\sin x(2\cos x-1)=0`


`\implies\sin x=0\text{ or }2\cos x-1=0`

From the first equation, we get two possible solutions at
`x=0` and
`x=\pi\approx3.14`.

From the second equation, we get


`2\cos x-1=0\implies\cos x=\frac12`

which has exact solutions at
`x=\frac\pi3` and
`x=\frac{5\pi}3`. Since
`\pi\approx3.14`, we can approximate these solutions by
`x=\frac\pi3\approx1.05` and
`x=\frac{5\pi}3\approx5.24`.