Question

Let the mean of the population be 38 instances of from 6" - 9" hatchings per nest, and let the standard deviation of the mean be 4. What sample mean would have a confidence level of 95% or a 2.5% margin of error? 32 34 36 38

Answer 1

I saw 34 I'm trying that now

Answer 2

Answer with explanation:

Mean of the population having 6"-9" Hatching =38

Standard Deviation =4

Confidence interval of 95% means that 95% of data lie within two standard deviations.

That is data values lie between 38-2×4 to 38 +2×4.

⇒Which is 38-8 to 38+8.

⇒30 to 46.

it is also given that margin of error is 2.5%.

So, the data value will lie between

`30-30*(2.5)/(100) {\text{to}} 46 +46*(2.5)/(100)\\\\ 30-0.75 {\text{to}}46+(115)/(100)\\\\ 29.25 {\text{to}}47.15`

Mean of beginning value to extreme value of 95% confidence level

`=(29.25+47.15)/(2)\\\\=38.20`

So, Sample mean of this observation having 2.5% margin of error = 38

Option D:→ 38