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3 votes
The formula P=a+b+c gives the perimeter P of a triangle with side lengths a,b, and c. How much greater is the is the perimeter of triangular field with sides that measure 33 yards, 56 yards, and 65 yards than the perimeter of a triangular field with sides that measure 26 yards, 49 yards, and 38 yards?

2 Answers

4 votes
(154-113)
41 yards bigger
answered
User Kloe
by
8.0k points
2 votes

Answer : 41 yards greater is the perimeter of 1st triangular field than the perimeter of 2nd triangular field.

Step-by-step explanation :

First we have to calculate the perimeter of 1st triangle.


P_1=a+b+c

Given:

a = 33 yards

b = 56 yards

c = 65 yards


P_1=33+56+65


P_1=154\text{ yards}

Now we have to calculate the perimeter of 2nd triangle.


P_2=a+b+c

Given:

a = 26 yards

b = 49 yards

c = 38 yards


P_2=26+49+38


P_2=113\text{ yards}

Now we have to calculate which triangle has greater perimeter and how much greater.


P_1-P_2=(154-113)\text{ yards}=41\text{ yards}

Therefore, 41 yards greater is the perimeter of 1st triangular field than the perimeter of 2nd triangular field.

answered
User Wenqiang
by
8.7k points

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