Question

A positive charge of 6.0 × 10-4 C is in an electric field that exerts a force of 4.5 × 10-4 N on it. What is the strength of the electric field

Answer 1

0.75

Step-by-step explanation:

Answer 2

The magnitude of the electric force exerted on a charge in an electric field is given by

`F=qE`

where

q is the charge

E is the magnitude of the electric field

In this problem, we have a charge of
`q=6.0 \cdot 10^(-4) C`, while the force exerted on it is
`F=4.5 \cdot 10^(-4)N`, so we can rearrange the previous formula to calculate the magnitude of the electric field:

`E=(F)/(q)=(4.5 \cdot 10^(-4) N)/(6.0 \cdot 10^(-4) C)=0.75 N/C`