Question

PLEASE HELP FAST!!!!

As a pendulum swings , the angle (theta) that it makes with the vertical changes through its swing. The force of gravity pulling on the bob is given by F=mg sin (theta), where g is equal to 9.8m/s^2. If the mass of the pendulum is 0.01 kg, what is the force pulling on the pendulum when it makes a 22.5 degree angle with the vertical?

Answer 1

The force would be 0.04.

This is found by using the formula:

F=mg sinθ
F = 0.01(9.8)sin (22.5)
F ≈ 0.04

Answer 2

We have been given that the formula for the force of gravity pulling on the bob is given by
`F=m* g* sin(\theta)`), where g is equal to
`9.8m/s^2`.

Now, we have been given that the mass of the bob of the pendulum is 0.01 kg and that the pendulum makes 22.5 degree angle with the vertical.

Thus, applying the given values in the formula of the given in the question, we get the formula to be:

`F=m* g* sin(\theta)=0.01*9.8* sin(22.5^(\circ))`

`\therefore F\approx0.0375` N