Question

How many moles of nitrogen are in 73.0g of nitrous oxide n2o

Answer 1

Hey there!:

Molar Mass

N2O = 44.013 g/mol


Therefore:

number of moles N :

73.0 g * 1 mol N2O / 44.013 g N2O * 2 mols N / 1 mol N2O


73.0 * 1 / 44.013 * 2 / 1 =


73.0 / 44.013 * 2 =


1.6586 * 2 => 3,31 moles of N


hope this helps!

Answer 2

Answer : The number of moles of nitrogen present in nitrous oxide is 3.32 moles.

Explanation : Given,

Mass of nitrous oxide = 73.0 g

Molar mass of nitrous oxide = 44 g/mole

Now we have to calculate the moles of
`N_2O`.

Formula used :

`\text{ Moles of }N_2O=\frac{\text{ Mass of }N_2O}{\text{ Molar mass of }N_2O}`

`\text{ Moles of }N_2O=(73.0g)/(44g/mole)=1.66moles`

Now we have to calculate the moles of nitrogen in nitrous oxide.

In
`N_2O` molecule, there are 2 moles of nitrogen atoms and 1 mole of oxygen atom.

As, 1 mole of
`N_2O` contains 2 moles of nitrogen

So, 1.66 moles of
`N_2O` contains
`1.66* 2=3.32` moles of nitrogen.

Therefore, the number of moles of nitrogen present in nitrous oxide is 3.32 moles.