asked 221k views
4 votes
**PLEASE HELP ASAP** Betsy is analyzing a quadratic function f(x) and a linear function g(x). Will they intersect?

Yes, at positive x-coordinates
Yes, at negative x-coordinates
Yes, at negative and positive x-coordinates
No, they will not intersect

**PLEASE HELP ASAP** Betsy is analyzing a quadratic function f(x) and a linear function-example-1
**PLEASE HELP ASAP** Betsy is analyzing a quadratic function f(x) and a linear function-example-1
**PLEASE HELP ASAP** Betsy is analyzing a quadratic function f(x) and a linear function-example-2
asked
User Led
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7.6k points

2 Answers

6 votes

Answer:

C. Yes, at negative and positive x-coordinates

Explanation:

I got it right on the test.

Hope this helps :)

answered
User PolyThinker
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8.2k points
4 votes
We analyze the chart and observe that the linear function is
y=x, since this relation holds for all values in the table. Drawing this line over the quadratic function shows that they intersect twice, at both the positive and negative x-coordinates.

This is by far the easiest way to solve this problem, but if you're interested in learning how to do it algebraically, read on! To prove this more rigorously, we can find that the equation of the parabola is
y=\frac13 x^2 - 2. Substituting in
y=x, we find that the intersection points occur where
\frac13 x^2 - 2 = x, or
\frac13 x^2 - x - 2 = 0, or
x^2 - 3x - 6 = 0.

This equation doesn't factor nicely, so we use the quadratic formula to learn that
x = (3 \pm √(3^2 - 4 \cdot 1 \cdot (-6)))/(2) = (3 \pm √(33))/(2). Hence, the x-coordinates of the intersection points are
(3 + √(33))/(2), which is positive, and
(3 - √(33))/(2), which is negative. This proves that there are intersection points on both ends of the axis.
answered
User Stasel
by
9.0k points
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