Question

Choose the correct simplification of d to the 7th power times g to the 13th power all over d to the 2nd power times g to the 7th power.

d9g20
1 over d to the 5th power times g to the 6th power
1 over d to the 9th power times g to the 20th power
d5g6

Answer 1

Correct answer would be d to the 5th power over g to the 6th power

Answer 2

Option 4

Explanation:

Given : d to the 7th power times g to the 13th power all over d to the 2nd power times g to the 7th power.

To find : The correct simplification

Solution :

d to the 7th power =
`d^7`

g to the 13th power =
`g^(13)`

d to the 7th power times g to the 13th power =
`d^7* g^(13)`

d to the 2nd power =
`d^2`

g to the 7th power =
`g^7`

d to the 2nd power times g to the 7th power =
`d^2* g^(7)`

According to question,

d to the 7th power times g to the 13th power all over d to the 2nd power times g to the 7th power.

`=(d^7* g^(13))/(d^2* g^7)`

`=d^(7-2)* g^(13-7)`

`=d^(5)* g^(6)`

Therefore, Option 4 is correct.