Question

If you shook the end of a rope up and down 5 times each second, what would be the period of the waves set up in the rope?

Answer 1

Shaking the rope at 5 times per second sets up waves with a frequency of 5 Hz. The period of these waves, which is the inverse of frequency, would be 0.2 seconds.

Step-by-step explanation:

When you shake the end of a rope up and down 5 times each second, you are creating waves with a certain frequency. The frequency is the number of complete waves that pass a given point in one second, and it is measured in hertz (Hz). Since you're shaking the rope 5 times per second, the frequency of the waves set up in the rope is 5 Hz.

The period of a wave is the time it takes for one complete wave cycle to pass a point. It is the inverse of the frequency. To calculate the period (T), you would use the formula:

T = 1 / f, where 'f' is the frequency.

So in this case:

T = 1 / 5 Hz = 0.2 seconds.

Therefore, the period of the waves set up in the rope is 0.2 seconds.

Answer 2

Shooking the rope up and down 5 times per seconds means that there are 5 cycles of the wave (or 5 crests) in one second, and so its frequency is
`f=5 Hz`.

The period T is the reciprocal of the wave's frequency, therefore it is

`T= (1)/(5 Hz)=0.20 s`