Question

These data show the ring sizes for a sample of 8 men. 12 10 11.5 11.5 12 9 9 11 What is the best approximation of the standard deviation for the ring size data?

Answer 1

The answer should be 1.10

Explanation:

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Answer 2

The population size of the above data is 8, that is N=8
The mean (average) = (12 +10+ 11.5 +11.5 +12 +9 +9 +11)/8
= 10.75
Standard deviation is the square root of variance, it is one of the measures of central dispersion, that is a measure of by how much the values in the data set are likely to differ from the mean.
In this case, Standard deviation, s= √(∑(x-m)²)/(n-1)
= 1.172
Thus, best approximation of the standard deviation is 1.17