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Find the product of 80x^4/y^3 ×xy/5x^2

1 Answer

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\bf ~~~~~~~~~~~~\textit{negative exponents}\\\\ a^(-n) \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^(-n) \qquad \qquad a^n\implies \cfrac{1}{a^(-n)} \\\\ -------------------------------\\\\ \cfrac{80x^4}{y^3}* \cfrac{xy}{5x^2}\implies \cfrac{80x^4xy}{y^35x^2}\implies \cfrac{80x^4xx^(-2)}{5y^3y^(-1)}\implies \cfrac{80x^4x^1x^(-2)}{5y^3y^(-1)} \\\\\\ \cfrac{16x^(4+1-2)}{y^(3-1)}\implies \cfrac{16x^3}{y^2}
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User NM Pennypacker
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