Question

Write a balanced equilibrium equation for the dissolution of nai in water. include phases.

Answer 1

The balanced equilibrium equation for the dissolution of NaI in water is NaI(s) ⇌ Na+(aq) + I−(aq), indicating that solid NaI dissolves into sodium and iodide ions in an aqueous solution.

Step-by-step explanation:

The dissolution of NaI in water can be represented by a balanced equilibrium equation that shows the dissociation of NaI into its ions. The equation is as follows:

NaI(s) ⇌ Na+(aq) + I−(aq)

Here, NaI is in the solid (s) phase, and the sodium (Na+) and iodide (I−) ions are in the aqueous (aq) phase, indicating that they are dissolved in water. This equation demonstrates the solubility of NaI in water and the ionic nature of this chemical equilibrium.

Answer 2

Step-by-step explanation:

The compound sodium iodide (NaI) is an ionic compound as there is formation of chemical bond by transfer of electrons from sodium to iodine.

Therefore, it is a polar molecule and we know that water is also a polar solvent. Hence, like dissolves like as a result, sodium iodide will dissociate into water.

The reaction equation will be as follows.

`NaI(s) + H_(2)O \rightarrow Na^(+)(aq) + I^(-)(aq)`