Question

Can anyone tell me how to do this? (Steps) and can you answer these two questions for me plz

Need by tomorrow

Answer 1

ax²+bx+c=0

The formula to solve for x is:


`x= \frac{-b(+/-) \sqrt{ b^(2)-4ac } }{2a}`


So for 3x²+13x+10=0, plug in the data

x=-13±√13²-4(3)(10) / 2(3)
x=-13±√169-120 / 6
x=-13±√49 /6
x=-13±7 / 6

x=-13+7/6
x=-6/6
x=-1

x=-13-7/ 6
x=-20/6 or 3.3repeating

3x²+14x+15=0
x=-14±√14²-4(3)(15) / 2(3)
x=-14±√196-180 /6
x=-14±√16 / 6

x=-14+4/6
x=-10/6 or 1.6repeating

x=-14-4/6
x=-18/6
x=-3