Question

Please help thanks very much

Answer 1

Question 1:

In this 45-45-90 right triangle, the hypotenuse has a length of
`x √(2)` and the leg has a length of
`x`

We want to solve for x. Let's start with the equation of
`x √(2) =10` and solve for x.


`x √(2) =10`

Divide both sides by the square root of 2.


`x=(10)/( √(2) )`

Simplify the fraction by multiply both the numerator and denominator by the sqaure root of 2.


`x=(10 √(2))/(2)`

`=5 √(2)`

Question 2:

Let's imagine a right triangle where the legs are 250 and we want to solve for the hypotenuse. Since the legs are congruent, this is a 45-45-90 right triangle.

Multiply 250 by the square root of 2 and use a calculator.


`250 √(2) \approx 353.6`

Hope this helps! :)