What positive number x satisfies the equation 3x^2 = 27^3?

Question

asked May 5, 2019 120k views

2 Answers

Kushalbhaktajoshi · Answer 1 · 2019-05-10T23:24:05+0000

3x^2=27^3

Simplify both sides of the equation

3x^2=19683

Then divide both sides by three

x^2=6561

find square root

x=81

Hope this helped :)