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Solve for x in the equation x^2-8x+41=0

Solve for x in the equation x^2-8x+41=0
asked 122k views
1 vote
Solve for x in the equation x^2-8x+41=0

asked
User Rahul Chawla
by
7.3k points

2 Answers

4 votes
The answer is x = 5.375
answered
User Annika
by
7.9k points
1 vote
x = [-(-8) +/- sqrt((-8)^2 -4*41)] / 2

x = ( 8 + sqrt (-100) / 2 and (8 - sqrt(-100) / 2

4 +or- 5i

answered
User Flowera
by
8.2k points
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