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What is the probability of (A) if P(AnB) =.20; P(AnC) =.16; and P(AnD) =.11 and we assume "A" can occur simultaneously only with "B,C,D"

What is the probability of (A) if P(AnB) =.20; P(AnC) =.16; and P(AnD) =.11 and we assume "A" can occur simultaneously only with "B,C,D"
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what is the probability of (A) if P(AnB) =.20; P(AnC) =.16; and P(AnD) =.11 and we assume "A" can occur simultaneously only with "B,C,D"

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User Jose Ananio
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1 Answer

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the probability of (A)
P(A)=P(AnB)*P(AnC)*P(AnD)
P(A)=0.20*0.16*0.11=0.0035---- > 0.35%

the answer is
the P(A)=0.35%
answered
User Mathieu Dubois
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