Question

How many nitrogen atoms are in a 3.37 mol sample of N2O?

Answer 1

Using a Avagadros number

Answer 2

Answer:
`40.6* 10^(23)` atoms

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles. and weighs equal to the molecular mass.

1 mol of
`N_2O` contains =
`2* 6.023* 10^(23)=12.046* 10^(23)` atoms of nitrogen

3.37 mol of
`N_2O` contains =
`(12.046* 10^(23))/(1)* 3.37=40.6* 10^(23)` atoms of nitrogen

Thus the number of nitrogen atoms in a 3.37 mol sample of
`N_2O` is
`40.6* 10^(23)`