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How many different 99-letter permutations can be formed from 77 identical h's and two identical t's?

How many different 99-letter permutations can be formed from 77 identical h's and two identical t's?
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How many different 99-letter permutations can be formed from 77 identical h's and two identical t's?

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User Amry
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1 Answer

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Assuming "99" and "77" are actually 9 and 7,


(9!)/(7!2!)=36
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User Dennis Hoer
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