Question

Same question as before

Answer 1

well is pretty much just their product, notice all you do is, multiply each term on one side, by the other terms, sum them up, and that's all,


`\bf (2-√(2))(3+√(2))\implies 2(3+√(2))~~~+~~~[-√(2)(3+√(2))] \\\\\\ 6+2√(2)~~~+~~~[-3√(2)-(√(2))^2]\implies 6+2√(2)~~~+~~~[-3√(2)-2] \\\\\\ 6+2√(2)-3√(2)-2\implies 6-2+2√(2)-3√(2)\implies 4-√(2)`