Question

A 1.0 × 103-kilogram car travels at a constant speed of 20. meters per second around a horizontal circular track. The diameter of the track is 1.0 × 102 meters. The magnitude of the car’s centripetal acceleration is

Answer 1

Centripetal acceleration is given by:


`a = (v^(2))/(r)` where r is the radius, and v is the tangential velocity.

The diameter of the track is 100m, so the radius is 50m.

So, the acceleration is:


`a = (20^(2))/(50) = 8 m/s^(2)`