Question

Draw the alkyne formed when 3,4-dichloroheptane is treated with an excess of strong base such as sodium amide

Answer 1

co2 is correct buddy

Answer 2

3-heptyne

Step-by-step explanation:

Hello,

In this case, we're talking about an elimination chemical reaction wherein the strong base promotes the elimination of both chlorine and hydrogen atoms bonded to the third and fourth carbons in the 3,4-dichloroheptane to form 3-heptyne as shown on the attached picture.

Best regards.