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A ball is thrown with an initial speed of 10. Meters per second. At what angle above the horizontal should the ball be thrown to reach the greatest height?

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The initial speed doesn’t matter. To reach the maximum height, you need to launch straight up ... 90 degrees above horizontal.

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User Nirmus
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Answer:

90 degree

Step-by-step explanation:

The height for the projectile motion is given by

H = u^2 Sin^2 theta/ 2g

Height is maximum when sin theta is maximum.

Sin theta is maximum when it's value is 1.

So the value of theta is 90 degree.

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