Question

An airplane flies 810 km in 1.5 hours. Find the constant of variation.

Answer 1

`\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{\underline{d}istance of 810 km in 1.5 \underline{h}ours}}{d=kh} \\\\\\ \textit{we know that } \begin{cases} h=1.5\\ d=810 \end{cases}\implies 810=k(1.5)\implies \cfrac{810}{1.5}=k\implies 540=k`

Answer 2

Answer : The value of constant of variation is, 540

Step-by-step explanation :

As we know that,

`\text{Distance}=\text{Speed}* \text{Time}`

That means,

d = s × t

Here,

's' is constant of variation.

Given:

d = distance = 810 km

t = time = 1.5 hr

Now put the values in the above expression, we get:

d = s × t

810 km = s × 1.5 hr

`s=(810km)/(1.5hr)=540km/hr`

Thus, the value of constant of variation is, 540