Question

Aanya wrote the four equations that are shown below. She examined them, without solving them, to determine which has exactly one solution. Which of aanya's equations has exactly one solution

A:6x-8=4(x-2)+2x
B:3(x-1)+2x=3(x-1)+2
C:7x+2-x=6(x+2)
D:4(x+3)+x=5(x+1)+7

Answer 1

B

This you answer!

Answer 2

B:3(x-1)+2x=3(x-1)+2

Explanation:

Aanya wrote the four equations that are shown below.

We need to check each equation and see which equations have same coefficient of x terms on both sides of equation.

A: 6x-8=4(x-2)+2x

Distribute 4 inside the parenthesis

6x-8=4x- 8+2x

We know 4x + 2x is 6x. So, both sides we have 6x. Hence no solution for this equation.

B:3(x-1)+2x=3(x-1)+2

Distribute 3 inside the parenthesis

3x - 3 + 2x = 3x - 3 + 2

5x - 3 = 3x- 3 + 2

Coefficient of x are not same on both sides. So this equation has exactly one solution.

C:7x+2-x=6(x+2)

Distribute 6 inside the parenthesis

6x + 2= 6x + 12

Both sides we have 6x. Hence no solution for this equation.

D:4(x+3)+x=5(x+1)+7

Distribute 4 and 5 inside the parenthesis

5x + 12= 5x + 5+ 12

Both sides we have 5x. Hence no solution for this equation.