asked 2.3k views
5 votes
you slide across home plate during baseball game. If you have a mass of 82 kg, and the coefficient of kinetic friction between you and the ground is 0.45, what is the force of friction acting on you?

asked
User Hoyhoy
by
7.9k points

2 Answers

4 votes

Answer:

362 rounded, a p e x users

Step-by-step explanation:

answered
User Masinger
by
8.5k points
3 votes

m = mass of the person = 82 kg

g = acceleration due to gravity acting on the person = 9.8 m/s²

F = normal force by the surface on the person

f = kinetic frictional force acting on the person by the surface

μ = Coefficient of kinetic friction = 0.45

The normal force by the surface in upward direction balances the weight of the person in down direction , hence

F = mg eq-1

kinetic frictional force on the person acting is given as

f = μ F

using eq-1

f = μ mg

inserting the values

f = (0.45) (82) (9.8)

f = 361.6 N

answered
User Chris Maggiulli
by
8.1k points

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