Answer:
1) First term = -105/2
2) The first option is the correct answer 9/2[ 2 + 26]
Explanation:
It is given that, 
The first term of the arithmetic sequence in which.... a27=-1/2 
 and the common difference is 2 
To find the First term 
First term of an AP be a and common difference d the nth term can be written as, 
an = a + (n-1)d 
Here n = 27 
d = 2 , a27 = -1/2 
a + (26 x 2) = -1/2 
a = -105/2 
 
From the figure We get an = 3n - 1 
To find first term a1 and ninth term s9 
a1 = 3 x 1 - 1 = 2 
a9 = 3x 9 - 1 = 26 
 
Sum of nth term of an AP 
n/2[first term + Last term] 
first term a1 and Last term = 26 
 
Sum of first 9 terms S9 
S9 = 9/2[ 2 + 26] 
First option is the correct answer