Question

Q.16 please
With steps

Answer 1

The equations

`2x^2+9x-5=0`

and

`2\left(t-\frac12\right)^2+9\left(t-\frac12\right)-5=0`

are really the same, we're just setting
`x=t-\frac12`, or
`t=x+\frac12`.

`2x^2+9x-5=(2x-1)(x+5)=0\implies x=\frac12,x=-5`

So we get

`t=\frac12+\frac12=1,t=-5+\frac12=-\frac92`