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5 votes
The largest tree in the world is the General Sherman sequoia in Sequoia National Park, California. It is 275 feet high, has a diameter of 36.5 feet, and has an estimated weight of 2,150 tons. Find the sequoia’s circumference to the nearest tenth of a foot. Use 3.14 for π. Explain how you found the answer.

1 Answer

4 votes

Answer:

114.6 ft

Explanation:

The circumference is found by multiplying the diameter by pi.

... C = πd

... C = 3.14×36.5 ft = 114.61 ft

Since the product has two decimal places, it must be rounded to express it to the nearest tenth foot. The hundredths digit is less than 5, so it is merely dropped.

... 114.61 ft ≈ 114.6 ft

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User Mdthh
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