Question

Three positive numbers are in the ratio 7:3:2. The sum of the smallest number to the largest number exceeds twice the remaining number by 30. Find the three numbers.

Answer 1

Thanks

Explanation:

Answer 2

The numbers are 70,30,20.

Explanation:

Let the three numbers be 7x,3x and 2x.

The sum of smallest and largest number is 7x+2x=9x.

According to question:

9x-30=2(3x)

Simplifying the equation:

9x-30=6x

Adding 30 both sides:

9x=6x+30 or,9x-6x=30

3x=30, x=10,

The numbers are 7x=7(10)=70

3x=3(10)=30

2x=2(10)=20.