Question

A triangle has a perimeter of 33cm. If the three sides of the triangle are n, 3n−4 3n−4 , and 3n−5 3n−5 , what is the length of each side?

Answer 1

6 , 14 , 13

Explanation:

n + 3n - 4 + 3n - 5 = 33

7n - 9 = 33

7n = 33 + 9

7n = 42

n = 6

So, 3n - 4 = 14 , 3n - 5 = 13

Answer 2

The perimeter is the sum of the sides.

n + (3n - 4) + (3n - 5) = 33

7n - 9 = 33

7n = 42

n = 6

3n-4=18-4=14

3n-5=13

Check: 6+14+13=33, good

Answer: 6 cm, 14 cm, 13 cm