Question

The play director spent 190190 hours preparing for a play. That time included attending 3535 rehearsals that took varying amounts of time and spending 93 \dfrac{3}{4}93 4 3 ? hours on other responsibilities related to the play. What question does the equation 35x+93\dfrac{3}{4}=19035x+93 4 3 ? =190 help answer?

Answer 1

Answer: it helps answer “What was the average length of each rehearsal?” Or C

Step-by-step explanation: 35x + 93 3/4=190

190 is total hours

(Hours of rehearsal) + (hours of the rest of the days) = (total hours preparing)

(35x)+(93 3/4)=(190)

(35) x (x) =(35x)

X is time per rehearsal and since it’s the average time not the exact time per rehearsal it helps answer the question “What was the average length of each rehearsal?” Your welcome:p

Answer 2

The equation
`35x+93(3)/(4)=190` gives average time spent on 35 rehearsals.

Explanation:

We have been given an equation
`35x+93(3)/(4)=190` and we are supposed to find that the given equation helps to find answer of what question.

We can see that
`93(3)/(4)` is time spent on other responsibilities related to play and 35x represents time spent on 35 rehearsals. The sum of these times equals to total time spent on preparing the play.

Now let us solve our equation step by step.

`35x+(375)/(4)=190`

After subtracting
`(375)/(4)` hours from 190 hours we will get time spent on 35 rehearsals.

`35x+(375)/(4)-(375)/(4)=190-(375)/(4)`

`35x=(760)/(4)-(375)/(4)`

`35x=(760-375)/(4)`

`35x=(385)/(4)`

`35x=96.25`

Time spent on 35 rehearsals is 96.25 hours and we are told that each rehearsal took different amount of time. Dividing 96.25 by 35 we will get average time spent on each rehearsal.

`(35x)/(35)=(96.25)/(35)`

`x=2.75`

Therefore, equation
`35x+93(3)/(4)=190` finds average time spent on 35 rehearsals.