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Help please

through the given point and perpendicular to the given equation write your answer in slope intercept form

1) ( -4 , 2) and 6x - y = 1

2) ( -3 , -5) and y = - x + 3

3) ( 1 , 4 ) and y = 1/2 x + 4

1 Answer

3 votes

Answer:

  1. y = (-1/6)x +4/3
  2. y = x -2
  3. y = -2x +6

Explanation:

A simple, mechanical way to do these (perpendicular lines) is ...

  • replace any constant with 0
  • swap the x- and y-coefficients, negating one
  • for point (h, k), replace x with (x-h) and y with (y-k)
  • solve for y (to get slope-intercept form)

1) (x+4) +6(y -2) = 0 . . . .after step 3 above

... x -8 = -6y . . . . . . . . . . eliminate parentheses, add the opposite of the y-term

... y = (-1/6)x +4/3 . . . . . divide by the y-coefficient

2) (y+5) = (x +3)

... y = x -2 . . . . . . . . . . . . . add -5

3) (1/2)(y -4) = -(x -1)

... 1/2y -2 = -x +1 . . . . . . . eliminate parentheses

... 1/2y = -x +3 . . . . . . . . . add 2

... y = -2x +6 . . . . . . . . . . . multiply by 2

_____

Comment on the graph(s)

The attached graphs show the original lines and points (1: red, 2: blue, 3: green). The original line is dashed, and the perpendicular line through the point is shown solid. This confirms the results above.

Help please through the given point and perpendicular to the given equation write-example-1
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User Papa
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