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What is the average rate of change for g(x)=(x+2)^2-9 from x=1 to x=4?

What is the average rate of change for g(x)=(x+2)^2-9 from x=1 to x=4?-example-1
asked
User Maraspin
by
8.6k points

2 Answers

2 votes

Answer:


Step-by-step explanation:


9


Step-by-step explanation:

The

average rate of change

of g(x) over an interval between 2 points (a ,g(a)) and (b ,g(b) is the slope of the

secant line

connecting the 2 points.


To calculate the average rate of change between the 2 points use.


¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

g

(

b

)

g

(

a

)

b

a

a

a

−−−−−−−−−−−−−−−


g

(

6

)

=

6

2

6

+

3

=

33


and

g

(

4

)

=

4

2

4

+

3

=

15


Thus the average rate of change between (4 ,15) and (6 ,33) is


33

15

6

4

=

18

2

=

9


This means that the average of all the slopes of lines tangent to the graph of g(x) between (4 ,15) and (6 ,33) is 9.

answered
User Hamdy
by
7.6k points
0 votes

Answer:

9

Step-by-step explanation:

Expand. (x+2)^2-9=x^2+4x-5. For x=1, the function equals 1^2+4*1-5=0.

4^2+4*4-5=16+16-5=27.

(27-0)/3= 9

answered
User Matiiss
by
8.1k points

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