Question

How would i solve this problem using log base 10

Answer 1

First isolate the power of 10 on the right side by dividing both sides by 5:

`100=5\cdot10^(0.3t)\implies20=10^(0.3t)`

Now you're free to take the logarithm and simplify where you can:

`\log_(10)20=\log_(10)10^(0.3t)=0.3t\log_(10)10=0.3t`

Then solve for
`t`:

`t=(\log_(10)20)/(0.3)\approx4.34`