Answer:
y = 1(x + 3)² - 6
Explanation:
The standard form of a quadratic function is
y = ax² + bx + c
The vertex form of a parabola is
y = a(x - h)² + k
where (h, k) is the vertex of the parabola.
h = -b/(2a) and k = f(h)
In the equation y= x² + 6x + 3
a = 1; b = 6; c = 3
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Calculate h
h = -6/(2×1)
h = -6/2
h = -3
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Calculate k
k = 1(-3)² + 6(-3) + 3
k = 9 - 18 +3
k = -6
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Write the vertex form of the equation
y = 1(x + 3)² - 6
The graph is a parabola with a vertex at (-3, -6).