Question

Can you help me on this question.

Answer 1

A(0, 0)

C(a, a)

The formula of a midpoint of AC:

`\left((x_A+x_C)/(2),\ (y_A+y_C)/(2)\right)`

Substitute:

`x=(0+a)/(2)=(a)/(2)\\\\y=(0+a)/(2)=(a)/(2)`

Answer:
`\left((a)/(2),\ (a)/(2)\right)`