Question

A gas mixture contains .150 mol of o2 and .211 mol of Ar gas. What is the mole fraction of o2 in the mixture

Answer 1

0.4155 is the mole fraction of oxygen gas in the mixture.

Step-by-step explanation:

Mole fraction is defined as ratio of moles of specific to the total moles of all the compounds present in the mixture.

`\chi_i=(n_i)/(n_1+n_2+..n_i)`

Moles of oxygen gas =
`n_1=0.150 mol`

Moles of argon gas =
`n_2=0.211 mol`

Mole fraction of oxygen gas =

=
`\chi_1=(n_1 )/(n_1+n_2)=(0.150 mol)/(0.150 mol+ 0.211 mol)=0.4155`

Mole fraction of argon gas =

=
`\chi_2=(n_2 )/(n_1+n_2)=(0.211 mol)/(0.150 mol+ 0.211 mol)=0.5845`

0.4155 is the mole fraction of oxygen gas in the mixture.

0.5845 is the mole fraction of argon gas in the mixture.

Answer 2

(Answer) The mole fraction of oxygen in the mixture is 0.415.

Mole fraction of a gas in a mixture of gases is the ratio of the moles of the gas to the sum of moles of all gases in the mixture.

Moles of oxygen gas in the mixture = 0.150

Moles of argon gas in the mixture = 0.211

Total moles of gases in the mixture = (0.150 + 0.211) = 0.361

Mole fraction of oxygen gas =
`(0.150)/(0.361) = 0.415`