Question

How many moles of NaCl are present in 1.63 liters of a 0.954 M solution?

Answer 1

1.56 mol

Explanation:

c = n/V Multiply both sides by V and transpose

n = Vc

c = 0.954 mol·L⁻¹

V =1.63 L Calculate the moles

n = 0.954 × 1.63

n = 1.56 mol