asked 235k views
5 votes
What equation is graphed in this figure?

y−4=−13(x+2)
y−3=13(x+1)
y+2=−3(x−1)
y−5=3(x−1)

What equation is graphed in this figure? y−4=−13(x+2) y−3=13(x+1) y+2=−3(x−1) y−5=3(x-example-1
asked
User Swan
by
8.3k points

2 Answers

3 votes

Answer:

y+2=−3(x−1)

Explanation:

answered
User A Fader Darkly
by
8.7k points
6 votes

Answer:

y + 2 = -3(x - 1) Option C

Explanation :

In given graph y intercept is (0,1)

So, we check all the equations whose y intercept is (0,1)

We know the slope intercept form of line

y = mx + b

where b is y intercept

We write every equation in slope intercept form

Start from equation (1)

y - 4 = -13(x+2)

y - 4 = -13x - 26

y = -13x -22

y intercept is -22

Second equation:

y - 3 = 13x + 13

y = 13x + 16 y intercept is 16

Third equation:

y + 2 = -3x + 3

y = -3x + 1

y intercept is 1

So this is correct answer.


answered
User Ezhik
by
8.8k points
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