Question

Help ASAP, need this right now

Answer 1

I'm assuming you're asked to find the equations for lines that fit the given descriptions.

In the first case, having no x-intercept means that the line must be horizontal and not
`x=0`, so it will be entirely determined by the y-intercept, which is -5. So the line has equation
`y=-5`.

In the second case, the line is parallel to
`4y-2x=7`, or equivalently
`y=\frac12x+\frac74`, which has slope
`\frac12`. Parallel lines have the same slope. With the point-slope formula, you can find its equation:

`y-(-7)=\frac12(x-2)\implies y=\frac12x-8`

In the third case, the line is perpendicular to
`-7+3y=6x`, or
`y=2x+\frac73`. Perpendicular lines have slopes that are negative reciprocals of one another. Here, the given line has slope 2, which means the slope of its perpendicular counterpart is
`-\frac12`. Point-slope formula again:

`y-6=-\frac12(x-(-3))\implies y=-\frac12x+\frac92`

In the fourth case, you first need to find the slope of such a line. Note that the x-coordinates are the same, which means the line will be vertical and the equation is determined entirely by the x-intercept. So the equation is
`x=7`.