Question

Solve: Find three consecutive even integers such that the sum of the smallest number and twice the middle number is 20 more than the largest number?

Answer 1

Answer: 8

Step-by-step explanation: 6,7,8 are the consecutive integers because 6+7(2)=20

Answer 2

We are given

Let's assume

smallest even integer =x

Since, each even integers are difference of 2

so, middle term =x+2

so, largest term =x+2+2=x+4

the sum of the smallest number and twice the middle number is 20 more than the largest number

so, we get

`x+2(x+2)=20+x+4`

now, we can solve for x

`x+2x+4=20+x+4`

`x+2x+4=x+24`

`3x+4=x+24`

`2x=20`

Divide both sides by 2

`x=10`

so, smallest even integer=10

middle even integer=12

largest even integer=14............Answer