The volume of a mixed amount of gas doubled, and the absolute temperature is doubled. According to the ideal gas law, how has the pressure of the gas changed

Question

asked Oct 10, 2019 19.5k views

2 Answers

Peter HvD · Answer 1 · 2019-10-17T10:27:27+0000

Answer : The pressure of the gas would be unchanged.

Explanation : Given,

Ideal gas law :
PV=nRT

where,

P = pressure of gas

V = volume of gas

T = temperature of gas

n = moles of gas

R = Gas constant

The expression for pressure is,

P=(nRT)/(V)

when the volume and temperature of gas doubled then the expression for pressure is,

P_1=(nR* 2T)/(2V)=(nRT)/(V)=P

From this we conclude that the
that means pressure of the gas would be unchanged.