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An information technology company produces 45% of its computer chips at a plant in St. Louis and the remainder of its chips at a plant in Chicago. It is known that 0.85% of the chips produced in St. Louis are defective, while 1.05% of the chips produced at the plan in Chicago are defective. What is the probability that a randomly chosen computer chip produced by this company is defective and was produced in St. Louis?

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User Hawkins
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2 Answers

5 votes

Final answer:

To find the probability that a randomly chosen computer chip produced by this company is defective and was produced in St. Louis, we multiply the probability of a chip being produced in St. Louis by the probability of a chip being defective given that it was produced in St. Louis.

Step-by-step explanation:

To find the probability that a randomly chosen computer chip produced by this company is defective and was produced in St. Louis, we need to calculate the joint probability. First, we find the probability of a chip being produced in St. Louis, which is 45%. Then, we calculate the probability of a chip being defective given that it was produced in St. Louis, which is 0.85%. Finally, we multiply these two probabilities together to get the joint probability:

Joint Probability = Probability of St. Louis * Probability of Defective | St. Louis

Joint Probability = 0.45 * 0.0085

Joint Probability = 0.003825

Therefore, the probability that a randomly chosen computer chip produced by this company is defective and was produced in St. Louis is 0.3825%.

answered
User Aserwin
by
8.0k points
2 votes

Answer:

the probability of the computer chip produced and defective is 0.003825

Step-by-step explanation:

The computation of the probability of the computer chip produced and defective is shown below

= Produced percentage × defective percentage

= 45% × 0.85%

= 0.003825

Hence, the probability of the computer chip produced and defective is 0.003825

The same is considered and relevant too

answered
User Dmuir
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7.9k points

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