Question

Which equation can you use to evaluate log 1/3^27

Answer 1

a on edge

Explanation:

Answer 2

To evaluate
`\log _{(1)/(3)}27` note that:

• 
  `(1)/(3)=3^(-1);`
• 
  `27=3^3.`

Use following properties:

1)
`\log_ab^k=k\log_ab;`

2)
`\log_(a^k)b=(1)/(k)\log_ab.`

Then

`\log _{(1)/(3)}27=\log_(3^(-1))3^3=3\log_(3^(-1))3=3\cdot (1)/(-1)\log_33=-3\log_33.`

Since
`\log_aa=1,` you have

`\log _{(1)/(3)}27=-3.`