asked 181k views
5 votes
Please Help, ASAP!!!!

At track practice, runners were to walk or jog twenty laps. Sam jogged 0.29 of the laps, Jim jogged 3/11

of the laps, Sue jogged 0.26 of the laps, and Bill jogged 2/7

. List the runners in order from least to greatest number of laps walked.

2 Answers

4 votes

SUE 0.26

SAM 0.29

JIM 3.63

BILL 5.71

hope this helps

answered
User Eric Speelman
by
8.6k points
2 votes

Answer:

Sue < Jim < Bill < Sam

Explanation:

We're given with:-

Number of lap jogged by Sam = 0.29

Number of lap jogged by Jim =
(3)/(11)

Number of lap jogged by Sue = 0.26

Number of lap jogged by Bill =
(2)/(7)

Let's convert each of the decimal numbers to fraction so that we can easily compare them.

Number of lap jogged by Sam =
(29)/(100)

Number of lap jogged by Sue =
(26)/(100)

We have the fractions:-


(29)/(100),
(3)/(11),
(26)/(100),
(2)/(7)

We need to have the same denominator for each fraction so that they can be compared.

So, we'll need to find out the Lowest common multiple of the denominators.

LCM of 100, 11, 100, 7 = 7700

Let's make each denominator same by multiplying


(29)/(100)*(77)/(77),
(3)/(11)*(700)/(700),
(26)/(100)*(77)/(77),
(2)/(7)*(1100)/(1100)

Upon multiplying, we get


(2233)/(7700), (2100)/(7700), (2002)/(7700), (2200)/(7700)

So,

Sam =
(2233)/(7700)

Jim =
(2100)/(7700)

Sue =
(2002)/(7700)

Bill =
(2200)/(7700)

Since all the denominators are now same, we can now order these fractions by comparing their numerators

Sue < Jim < Bill < Sam



answered
User AntiElephant
by
8.4k points
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