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Find the area and the perimeter of a rectangle with a length of 5 feet and a width of 4 5/9 feet. Write each answer as a fraction and as a decimal. Use bar notation if necessary. Please help me out!!

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User JLRishe
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\bf \textit{area of a rectangle}\\\\ A=Lw~~ \begin{cases} L=5\\ w=4(5)/(9)\\[0.8em] \qquad (4\cdot 9+5)/(9)\\[0.8em] \qquad (41)/(5) \end{cases}\implies A=5\cdot \cfrac{41}{5}\implies \stackrel{fraction}{A=\cfrac{41}{1}}\implies \stackrel{decimal}{A=41} \\\\[-0.35em] \rule{34em}{0.25pt}



\bf \textit{perimeter of a rectangle}\\\\ A=2(L+w)\qquad \implies A=2\left(5+\cfrac{41}{5} \right) \implies A=2\left( \cfrac{25+41}{5} \right) \\\\\\ A=2\left( \cfrac{66}{5} \right)\implies A=\cfrac{132}{5}\implies \stackrel{fraction}{A=26(2)/(5)}\implies \stackrel{decimal}{A=26.4}

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User TOLULOPE ADETULA
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